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Question:

Amongst the following, the lowest degree of paramagnetism per mol of the compound at 298 K will be shown by: FeSO4.6H2O, NiSO4.6H2O, MnSO4.4H2O, CuSO4.5H2O

FeSO4.6H2O

NiSO4.6H2O

MnSO4.4H2O

CuSO4.5H2O

Solution:

Amongst the given compounds CuSO4.5H2O has less number of unpaired electrons, so it has the lowest degree of paramagnetism. Hence option D is correct.