Question:

An alternating voltage v(t)=220sin(100πt) volt is applied to a purely resistive load of 50Ω. The time taken for the current to rise from half of the peak value to the peak value is

2.2 ms

7.2 ms

3.3 ms

5 ms

Correct option is C. 3.3 ms
V(t)=220sin(100πt) volt
time taken, t = θ/ω = π/(3*100π) = 1/300 sec = 3.3 ms.