5 × 10⁻¹⁴
6 × 10⁻¹⁵
5 × 10⁻¹⁶
3 × 10⁻¹⁶
H₂S⇌ 2H⁺ + S²⁻
0.1 - α 0.2 + 2α α
Keq = K₁ × K₂ = 1.2 × 10⁻²⁰
1.2 × 10⁻²⁰ = (0.2 + 2α)²(α) / (0.1 - α)
As Keq is too small, α <<< 0.1
Therefore, 0.2 + 2α ≈ 0.2
0.2² × α = 1.2 × 10⁻²⁰
α = 3 × 10⁻¹⁶