80H
0.044H
0.08H
0.065H
Resistance of lamp by ohm's law, R = V/I = 80/10 = 8Ω
When inductor is connected in series and source is applied, V = IZ
V = I√(R² + (ωL)²)
Given, I = 10 A
for lamp to work, ∴ 220 = 10√(8² + (2 × π × 50 × L)²)
Solving, L = 0.0648 H