An electric dipole is placed at an angle of 30° with an electric field intensity 2×10⁵ N/C. It experiences a torque equal to 4 Nm. The charge on the dipole, if the dipole length is 2 cm, is :

Step 1: Dipole moment of dipole
Given the dipole length l=2 cm=2/100 m
So, the Dipole moment of dipole will be
P=lq=(2/100)q
P=0.02q
Step 2: Torque acting on dipole →τ=→P×→E
→ τ=PEsinθ
Or,4 Nm=(0.02q)(2×10⁵ N/C)sin30°
Or,q=200×10⁻⁶C=2mC
Hence, Option C is correct