Eduprobe
Question:
An electric field of 1000 V/m is applied to an electric dipole at an angle of 45°. The value of electric dipole moment is 10⁻⁹ C.m. What is the potential energy of the electric dipole?
7 × 10⁻⁷ J
7 × 10⁻⁷ J
60 × 10⁻⁸ J
50 × 10⁻⁹ J
Solution:
U = −→P ⋅ →E = −PEcosθ = −(10⁻⁹)(10³)cos45° = −7.07 × 10⁻⁷ J ≈ −7 × 10⁻⁷ J.