−110J
−110J
−110J
−110J
Potential difference between two points ΔV=work done per unit charge=∫→F.→dr/q=∫q→E.→dr/q
ΔV=−∫→E.→dr.. (i)
E=25^i+30^jand coordinates of given point →r=2^i+2^j
→dr=dx^i+dy^j
substituting values in equation (i)
ΔV=−∫→r→0(25^i+30^j).(dx^i+dy^j)
ΔV=−∫2025dx+∫2030dy=[−25x]20+[−30y]20=−50−60=−110V
V−Vorigin=−110J
given Vorigin=0
V=−110J
hence correct answer is option A