An electron in a hydrogen atom undergoes a transition from an orbit with quantum number ni to another with quantum number nf. Vi and Vf are respectively the initial and final potential energies of the electron. If Vi/Vf = 6.25, then the smallest possible nf is?
Solution:
Vi/Vf = 6.25 We have E ∝ Z2/n2 V = 2E Vi = 1/ni2 Vf = 1/nf2 nf2/ni2 = 6.25 nf/ni = 2.5 nf = 5/2 ni When ni = 2, nf = 5