An ideal gas is taken through the cycle A→B→C→A, as shown in the figure. If the net heat supplied to the gas in the cycle is 55 J, the work done by the gas in the process C→A is?
-15 J
-5 J
-10 J
-20 J
Solution:
Work done in cyclic process is area under the curve = 10J 5 = WCA + 10 WCA = 5 -10 = -5 J