An inductor 20mH, a capacitor 100µF and a resistor 50Ω are connected in series across a source of emf, V=10sin314t. The power loss in the circuit is?

L=20mH
C=100µF
R=50Ω
V=10sin(314t)
V0=10, ω=314
XL=ωL=314 × 20 × 10⁻³ =6.28Ω
XC=1/ωC=1/(314 × 100 × 10⁻⁶) =31.8Ω
Z=√(R²+(XC−XL)²)=√(50²+(31.8−6.28)²)=√(2500+625.8) =56.1Ω
Power loss P=V₀²/2Z²R = (10²)/(2(56.1)²) * 50 = 0.79W