An object 5.0 cm in length is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image, its nature, and its size.

Given: u = -20 cm, f = R/2 = 15 cm, Size of object, h = 5 cm
Let size of image be h'
From mirror formula, 1/u + 1/v = 1/f
1/-20 + 1/v = 1/15
1/v = 1/15 + 1/20
1/v = (4+3)/60 = 7/60
v = 60/7 = 8.57 cm
The image is formed 8.57 cm behind the mirror. It is virtual and erect.
Magnification, m = -v/u = 8.57/20 = 0.428
Also, m = h'/h = h'/5
From above, h'/5 = 0.428
h' = 2.14 cm