An oil funnel made of tin sheet consists of a 10 cm long cylindrical portion attached to a frustum of a cone. If the total height is 22 cm, diameter of the cylindrical portion is 8 cm and the diameter of the top of the funnel is 18 cm, find the area of the tin sheet required to make the funnel.

Given:Radius(R)of upper circular end of frustum part =18/2=9cmRadius(r)of lower circular end of frustum part = Radius of circular end of cylindrical part =8/2=4cmHeight(h1)of frustum part=22−10=12cmHeight(h2)of cylindrical part=10cmSlant height (l) of frustum part =√(R−r)²+h₁²=√(9−4)²+12²=√25+144=√169=13cmArea of tin sheet required = CSA of frustum part + CSA of cylindrical part=π(R+r)l+2πrh₂=22/7×(9+4)×13+2×22/7×4×10=22/7[169+80]=22×249/7=7824/7 cm²