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Question:

An open vessel at 27°C is heated until two-fifth of the air (assumed as an ideal gas) in it has escaped from the vessel. Assuming that the volume of the vessel remains constant, the temperature at which the vessel has been heated is:

500K

720oC

500oC

750oC

Solution:

2/5 air escaped from vessel, ∴ 3/5 air remains in vessel.

P and V constant

n₁T₁ = n₂T₂

n₁(300) = (3/5n₁)T₂

⇒T₂ = 500K.