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Question:

A→Ph−SO2Cl→B→KOH→C→C2H5I→D. 'C' is water soluble. Correct structure of A and D are?

R−NH−R,Ph−SO2−NR2−C2H5

R−NH2,Ph−SO2−N(R)−(C2H5)2+I−

R−NH2,Ph−SO2−NR−I

R2NH,Ph−SO2−NR2−(C2H5)+I−

Solution:

Correct option is A. R−NH2,Ph−SO2−N(R)−(C2H5)2+I−
Solution:- (A)R−NH2,Ph−SO2−NR−(C2H5)2+I−
R−NH2→Ph−SO2ClPh−SO2−NHR→−H2OKOHK+[PhSO2NR]−→−KI2C2H5IPh−SO2−N(C2H5)2+
Hence
A=R−NH2
B=Ph−SO2−NR−