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Question:

At 143 K, the reaction of XeF4 with O2F2 produces a xenon compound Y. The total number of lone pair(s) electrons present on the whole molecule of Y is _________.

19

Solution:

Correct option is A. 19
XeF4 + O2F2 → XeF6 (Y) + O.
XeF6 contains 3 lone pairs on each F and 1 lone pair on Xe. Therefore, the total number of lone pairs in molecule Y = 3 × 6 + 1 = 19