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Question:

At 300K, 36g of glucose present per litre in its solution has an osmotic pressure of 4.98 bar. If the osmotic pressure of the solution is 1.52 bar at the same temperature, what would be its concentration?

22gL⁻¹

36gL⁻¹

11gL⁻¹

42gL⁻¹

Solution:

4.98 = 36 × S × 300 / 180 × 1
S = 0.083 bar L mol⁻¹ K⁻¹
π₂ = n₂ST₂/V₂
1.52 = n₂ × 0.083 × 300 / V₂
n₂/V₂ = 0.061 mol L⁻¹ = 11gL⁻¹