devarshi-dt-logo

Question:

At 300K and 1 atmospheric pressure, 10 mL of a hydrocarbon required 55 mL of O2 for complete combustion and 40 mL of CO2 is formed. The formula of the hydrocarbon is:

C4H8

C4H7Cl

C4H6

C4H10

Solution:

CxHy + (x + y/4)O2 → xCO2 + y/2H2O
10 10(x + y/4) 10x
By given data,
10(x + y/4) = 55 .. (1)
10x = 40 .. (2)
∴x = 4, y = 8
→C4H8
Hence, option A is correct.