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Question:

At 518°C, the rate of decomposition of a sample of gaseous acetaldehyde, initially at a pressure of 363 Torr, was 1.00 Torr s⁻¹ when 5?

0

3

1

2

Solution:

Let x be the order of reaction,
CH₃CHO → d[CH₃CHO]/dt = k[CH₃CHO]ˣ
PV = nRT
P = CRT ∴ C = P/RT
(1/RT)d[CH₃CHO]/dt = k[CH₃CHO]ˣ
Rate = 1 Torr s⁻¹ when 5