" />
" />0.24
0.48
0.16
0.36
Hardy-Weinberg equation is p² + 2pq + q² = 1. Here p is the frequency of the "A" allele and q is the frequency of the "a" allele in the population. Hence, frequency of heterozygous genotype = 2pq = 2 x 0.6 x 0.4 = 0.48. So, the correct answer is 0.48