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Question:

Both the nucleus and the atom of some element are in their respective first excited states. They get de-excited by emitting photons of wavelengths λN, λA respectively. The ratio λN/λA is closest to

10𕒺

10󔼒

10

10𕒵

Solution:

EAEB=hc/λAhc/λN
So, EA/EN=λN/λA
As order of EA=eV and order of EN=MeV
∴λN/λA=1eV/1MeV=1/106=10-6
So option A is correct Answer