Eduprobe
Question:
Calculate Δ∞HOAc (in S cm² mol⁻¹) using appropriate molar conductances of the electrolytes listed in the given table at infinite dilution in H₂O at 25°C. Electrolyte: KCl, KNO₃, HCl, NaOAc, NaCl. Δ∞ (S cm² mol⁻¹): 149.9, 145.0, 426.2, 91.0, 126.5, 217.5, 305, 517.2, 390.7
217.5
305
390.7
517.2
Solution:
Reaction: HCl + NaOAc → NaCl + HOAc
Now, λ∞HOAc = λ∞NaOAc + λ∞HCl - λ∞NaCl = (91.0 + 426.2 - 126.5) S cm² mol⁻¹ = 390.7 S cm² mol⁻¹