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Question:

Calculate I for the given circuit diagram.

5 A

10 A

2.5 A

20 A

Solution:

For the wheatstone bridge part, the bridge resistance can be ignored. For this part, we have two branches each having two 5 ohm resistors. 1/RW = 1/R1 + 1/R2 where, R1 = R2 = 5 + 5 = 10 Ω because they are in series. Hence, RW = 5 Ω The wheatstone bridge is parallel to a 5 ohm resistor. Hence total equivalent resistance, 1/Req = 1/RW + 1/5 ⇒ Req = 2.5 Ω I = V/R = 25/2.5 = 10 A