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Question:

Calculate the amount of carbon dioxide that could be produced when (i) 1 mole of carbon is burnt in air. (ii) 1 mole of carbon is burnt in 16 g of dioxygen. (iii) 2 moles of carbon are burnt in 16 g of dioxygen.

Solution:

(i) 1 mole of carbon is burnt in air.
C+O2→CO2
1 mole of C produces 1 mole of CO2 which corresponds to 44 g of CO2
(ii) 1 mole of carbon is burnt in 16 g of dioxygen.
16 g of dioxygen corresponds to 16/32 = 0.5 moles.
Here, dioxygen is the limiting reagent. It will produce 0.5 moles of CO2 which corresponds to 0.5 × 44 = 22 g of CO2
(iii) 2 moles of carbon are burnt in 16 g of dioxygen.
16 g of dioxygen corresponds to 16/32 = 0.5 moles.
Here, dioxygen is the limiting reagent. It will produce 0.5 moles of CO2 which corresponds to 0.5 × 44 = 22 g of CO2