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Question:

Calculate the emf of the following cell at 25℃. Ag(s)|Ag+(10⁻³M)||Cu²+(10⁻¹M)|Cu(s) [Given, E⁰cell=+0.46V and log₁₀n=n]

Solution:

2Ag + Cu⁺² → 2Ag⁺ + Cu
Ecell = E⁰cell - 0.0591/n log[Ag⁺]²/[Cu⁺²]
= 0.46 - 0.0591/n log(10⁻³)²/10⁻¹
= 0.46 + 0.14775
= 0.60775 V