devarshi-dt-logo

Question:

Calculate the shortest wavelength in the Balmer series of hydrogen atom. In which region (infra-red, visible, ultraviolet) of hydrogen spectrum does this wavelength lie?

Solution:

Wavelength in the Balmer series of H-atom:
1λ=1.097×107×(1n12−1n22)m−1
For shortest wavelength in the Balmer series:
n1=2
n2=∞
∴1λmin=1.097×107×(122−1∞)m−1
λmin=41.097×107m=3.646×10−7m=364.6nm
This wavelength lies in the ultraviolet region.