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Question:

Charge -q and +q located at A and B, respectively, constitute an electric dipole. Distance AB = 2a, O is the mid point of the dipole and OP is perpendicular to AB. A charge Q is placed at P where OP = y and y >> 2a. The charge Q experiences an electrostatic force F. If Q is now moved along the equatorial line to P' such that OP' = (y/3), the force on Q will be close to L : (y/3 >> 2a)

3F

27 F

9F

F/3

Solution:

FA=kP/y^3Q=F
FB=EBQ
FB=kP/y^3
(3)^3Q=27FA→27F.