-1;
1
0
2
The correct option is D 2
The value of (1+tanθ+secθ)(1+cotθ−cosec θ) = (1+sinθ/cosθ+1/cosθ)(1+cosθ/sinθ−1/sinθ) = (cosθ+sinθ+1)/cosθ * (sinθ+cosθ−1)/sinθ = (sinθ+cosθ)²−1²/sinθcosθ = sin²θ+cos²θ+2sinθcosθ−1/sinθcosθ = 2sinθcosθ/sinθcosθ = 2