Complete the following nuclear reaction for α and β decay: (i) ₉₂²³⁸U → ?

i) ₉₂²³⁸U → ? + ₂⁴He + λ
Since ²³⁸U ejects Helium + Q
∴ It gives:-
₉₂²³⁸U → ₉₀²³⁴Th + ₂⁴He + Q
ii)₁₁²²Na → ₁₀²²Ne + ? + V
β Particle will be given.
₁₁²²Na → ₁₁²²Ne + β⁻ + V