Complete the following reaction equation:
(i) C6H5N2Cl + H3PO2 + H2O →
(ii) C6H5NH2 + Br2(aq) →

i) C6H5N2Cl + H3PO2 + H2O → C6H6 + N2 + H2PO3 + HCl

This is a reduction reaction where the diazonium salt (C6H5N2Cl) is reduced to benzene (C6H6) by hypophosphorous acid (H3PO2). Nitrogen gas (N2) is evolved as a byproduct, and phosphoric acid (H2PO3) and hydrochloric acid (HCl) are formed.

ii) C6H5NH2 + Br2(aq) → C6H2Br3NH2 + 3HBr

This is an electrophilic aromatic substitution reaction where bromine (Br2) reacts with aniline (C6H5NH2). The amino group (-NH2) is an activating group and ortho/para directing. Therefore, the reaction leads to tribromination of the benzene ring, resulting in 2,4,6-tribromoaniline (C6H2Br3NH2) and hydrobromic acid (HBr).