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Question:

Consider the 3rd orbit of He+ (Helium), using a non-relativistic approach, the speed of the electron in this orbit will be [given K = 9 × 10⁹ constant, Z = 2 and h (Planck's Constant) = 6.6 × 10⁻³⁴ Js]

3.0 × 10⁸ m/s

0.73 × 10⁶ m/s

1.46 × 10⁶ m/s

2.92 × 10⁶ m/s

Solution:

v = (2.19 × 10⁶) Z/n
v = (2.19 × 10⁶) 2/3
v = 1.46 × 10⁶ m/s