devarshi-dt-logo

Question:

Consider an electric field E = E0 ^x, where E0 is a constant. The flux through the shaded area (as shown in the figure) due to this field is:?

E0a2

√2 E0a2

E0a2√2

2 E0a2

Solution:

Flux through the area = Electric field × Area projected to the field
Φ = E A cos 45° = E0 (√2 a²) × 1/√2 = E0a²