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Question:

Consider the following bromides: The correct order of SN1 reactivity is:

B>A>C

B>C>A

A>B>C

C>B>A

Solution:

In B, the carbocation formed is resonance stabilized. So this is the most reactive compound. In C, the carbocation formed is 2o. In A, the carbocation formed is 1o. Therefore, C is more stable than A. So, the order is B>C>A.