Consider the following reaction (unbalanced) Zn + hot conc. H₂SO₄ → G + R + X Zn + conc. NaOH → T + Q G + H₂S + NH₄OH → Z (a precipitate) + X + Y Choose the correct options(s)

Correct option is D. Z is dirty white in colour.
Zn + H₂SO₄ (hot and conc.) → G + R + X
Zn + H₂SO₄ → ZnSO₄ (G) + SO₂ (R) + 2H₂O (X)
Zn + NaOH (conc.) → Na₂ZnO₂ (T) + H₂ (Q)
ZnSO₄ + H₂S + NH₄OH → ZnS (Z) + (NH₄)₂SO₄ (Y) + H₂O (X)
Thus,
The bond order of Q (H₂) is 1.
The oxidation state of Zn in Na₂ZnO₂ is +2.
R is a V-shaped molecule.
Z is dirty white in colour.