devarshi-dt-logo

Question:

Consider the following relations for emf of an electrochemical cell: (i) EMF of cell = (Oxidation potential of anode) - (Reduction potential of cathode) (ii) EMF of cell = (Oxidation potential of anode) + (Reduction potential of cathode) (iii) EMF of cell = (Reduction potential of anode) + (Reduction potential of cathode) (iv) EMF of cell = (Oxidation potential of anode) - (Oxidation potential of cathode) Which of the above relation(s) is correct?

(i) and (ii)

(iii) and (iv)

(ii) and (iv)

(iii) and (i)

Solution:

The EMF of a cell is given by the following expressions:
EMF of a cell = Reduction potential of cathode - Reduction potential of anode
= Reduction potential of cathode + Oxidation potential of anode
= Oxidation potential of anode - Reduction potential of anode
Hence, the relations (ii) and (iv) are correct.
Hence, the correct option is (ii) and (iv).