Formation of A and B from C has highest enthalpy of activation
Activation enthalpy of form C is 5 kJ mol⁻¹ less than that to form D
C is the thermodynamically stable product
D is kinetically stable product
Correct option is D. Activation enthalpy of form C is 5 kJ mol⁻¹ less than that to form D
A + B → C + D
Activation enthalpy for C = 20 - 5 = 15 kJ/mol
Activation enthalpy for D = 15 - 5 = 10 kJ/mol.