Sc³⁺<Ti³⁺<Ti²⁺<V²⁺
V²⁺<Ti²⁺<Ti³⁺<Sc³⁺
Sc³⁺<Ti³⁺<V²⁺<Ti²⁺
Ti³⁺<Ti²⁺<Sc³⁺<V²⁺
Correct option is A. Sc³⁺<Ti³⁺<Ti²⁺<V²⁺
Solution:- (A) Sc³⁺<Ti³⁺<Ti²⁺<V²⁺
a) Ti²⁺=1s²2s²2p⁶3s²3p⁶
Unpaired electrons=2
Spin only magnetic moment(μ)=√2(2+2)=√8 B.M
b) Ti³⁺=1s²2s²2p⁶3s²3p⁶
Unpaired electrons=1
μ=√1(1+2)=√3 B.M
c) V²⁺=1s²2s²2p⁶3s²3p⁶
μ=√3(3+2)=√15 B.M
d) Sc³⁺=1s²2s²2p⁶3s²
μ=0