7
Correct option is A. 7
r=k[A]ᵃ[B]ᵇ[C]ᶜ
By experiment no.1 and 2, b=0
By experiment no.1 and 3, c=1
By experiment no.1 and 4, a=1
r=K[A]¹[B]⁰[C]¹
From Ex. no.1
6×10⁻⁵=k(0.2)(0.1)
k=3×10⁻³ mol⁻¹dm³s⁻¹
Given [A]=0.15M; [B]=0.25M; [C]=0.15M
r=k[A]¹[B]⁰[C]¹=3×10⁻³×0.15×1×0.15=3×0.0225×10⁻³=6.75×10⁻⁵ mol dm⁻³sec⁻¹
Y=6.75≈7
Hence, the correct answer is 7