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Question:

Consider two identical galvanometers and two identical resistors with resistance R. If the internal resistance of the galvanometers Rg < R/2, which of the following statement(s) about any one of the galvanometers is(are) true?

The maximum current range is obtained when all the components are connected in parallel

The maximum current range is obtained when the two galvanometers are connected in series and the combination in parallel with both the resistors

The maximum voltage range is obtained when all the components are connected in series

The maximum voltage range is obtained when the two resistors and one galvanometer are connected in series, and the second galvanometer is connected in parallel to the first galvanometer

Solution:

For maximum voltage, Vmax = I(Rg + Req). This would happen when all components are in series. For maximum current, Req will be the parallel combination of two shunts and one galvanometer since in that case max current would flow through Rg. Answer is A and C options.