Construct a ΔABC in which CA=6cm, AB=5cm and ∠BAC=45°. Then construct a triangle whose sides are 3/5 of the corresponding sides of ΔABC.

Steps Of construction
Step1:Draw a line AB=5cm
Step2:With A as center Measure 45° using Protractor and draw a ray AX→
Step3:With B as center Cut an arc of Radius 6cm on the AX→
Step4:Mark the intersection as C Join B,C
Step5:Now divide the line AB in the ratio 3/5
Step6:Mark a point B’ 3cm apart from A on the line AB
Step7:Draw a line parallel to BC passing through B’
Step8:Mark the intersection as C’