Construct a triangle XYZ in which ∠Y = 30°, ∠Z = 90° and XY + ZX + YZ = 11 cm.

Steps of Construction:

1. Draw a line segment AB = 11 cm (= PQ + QR + RP).
2. At A, construct an angle of 30° and at B, an angle of 90°.
3. Bisect these angles. Let the bisectors of these angles intersect at a point X.
4. Draw perpendicular bisectors ST of AX and UV of BX. Let ST intersect AB at Y
5. Join XY and XZ. Then, XYZ is the required triangle.