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Question:

Daniel is painting the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint, 100 sq m of area is painted. How many cans of paint will she need to paint the room?

Solution:

Area to be painted = area of the walls + area of ceiling = 2(hl + hb) + lb = [2 × (7 × 15 + 7 × 10) + (15 × 10)] = 500 sq m
No. of cans required = 500 / 100 = 5
Hence, 5 cans are required to paint the walls and the ceiling of the cuboidal hall.