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Question:

Decide, among the following sets, which sets are subsets of one and another: A = {x: x ∈ R and x satisfies x² - x + 12 = 0}, B = {2, 4, 6}, C = {2, 4, 6, 8,...}, D = {6}

Solution:

A=x:x∈Rand x satisfiesx2𕒼x+12=02 and 6 are the only solutions ofx2𕒼x+12=0.∴A=2,6B=2,4,6C=2,4,6,8,D=6Clearly,D⊂A⊂B⊂CHence,A⊂B,A⊂C,B⊂C,D⊂A,D⊂B,D⊂C