Dilution process of different aqueous solutions with water are given in LIST-I. The effects of dilution of the solutions on [H+] are given in LIST-II. (Note: Degree of dissociation (α) of weak acid and weak base is <<1; degree of hydrolysis of salt <<1; [H+] represents the concentration of H+ ions). LIST-I LIST-II P. (10 mL of 0.1 M NaOH + 20 mL of 0.1 M acetic acid) diluted to 60 mL 1. the value of [H+] does not change on dilution Q. (20 mL of 0.1 M NaOH + 20 mL of 0.1 M acetic acid) diluted to 80 mL 2. the value of [H+] change to half of its initial value on dilution R. (20 mL of 0.1 m HCl + 20 mL of 0.1 m ammonia solution) diluted to 80 mL 3. the value of [H+] changes to two times of its initial value on dilution S. 10 mL saturated solution of Ni(OH)2 in equilibrium with excess solid Ni(OH)2 is diluted to 20 mL (solid Ni(OH)2 is still present after dilution). 4. the value of [H+] changes to 1/√2 times of its initial value on dilution 5. the value of [H+] changes to √2 times of its initial value on dilution Match each process given in LIST-I with one or more effect(s) in LIST-II. The correct option is:<p></p>

Dilution process of different aqueous solutions with water are given in LIST-I. The effects of dilution of the solutions on [H+] are given in LIST-II. (Note: Degree of dissociation (α) of weak acid and weak base is <<1; degree of hydrolysis of salt <<1; [H+] represents the concentration of H+ ions). LIST-I LIST-II P. (10 mL of 0.1 M NaOH + 20 mL of 0.1 M acetic acid) diluted to 60 mL 1. the value of [H+] does not change on dilution Q. (20 mL of 0.1 M NaOH + 20 mL of 0.1 M acetic acid) diluted to 80 mL 2. the value of [H+] change to half of its initial value on dilution R. (20 mL of 0.1 m HCl + 20 mL of 0.1 m ammonia solution) diluted to 80 mL 3. the value of [H+] changes to two times of its initial value on dilution S. 10 mL saturated solution of Ni(OH)2 in equilibrium with excess solid Ni(OH)2 is diluted to 20 mL (solid Ni(OH)2 is still present after dilution). 4. the value of [H+] changes to 1/√2 times of its initial value on dilution 5. the value of [H+] changes to √2 times of its initial value on dilution Match each process given in LIST-I with one or more effect(s) in LIST-II. The correct option is:

(P). CH3COOH 0.1M, 20ml + NaOH 0.1M, 10ml → CH3COONa + H2O The final solution will be a buffer of CH3COOH and CH3COONa as CH3COOH is not completely neutralized by NaOH. The final moles of CH3COOH = moles of CH3COONa = 0.001 mol pH = pKa + log[CH3COO⁻]/[CH3COOH] ⇒ [H+] will not change on dilution as concentration of salt and acid does not change on dilution. ∴Correct match : P→4 (Q). CH3COOH 0.1M, 20ml + NaOH 0.1M, 20ml → CH3COONa 0.025M, 80ml + H2O [OH⁻] = √KHC = √(kwkaC) [H+]1 = √kwkaC [H+]2 [H+]1 = √C1/C2 = √0.05/0.025 = √2 ∴Correct match : Q→3 (R). NH4OH 0.1M, 20ml + HCl 0.1M, 20ml → NH4Cl 0.025M, 80ml [H+] = √KHC [H+]2/[H+]1 = √C2/C1 = 1/√2 ∴Correct match : R→2 (S). Because of dilution solubility does not change so [H+]=constant.

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