Eduprobe
Question:
limx→0(1−cos2x)(3+cosx)xtan4x is equal to:
2
1
4
12
Solution:
limx→0\frac{1−cos2x}{x}(tan4x)(3+cosx)
limx→0\frac{2(sinx)^2}{x^2}\frac{4x}{tan4x}(3+cosx)=2×1×14×1×(3+1)=2.
2
1
4
12
limx→0\frac{1−cos2x}{x}(tan4x)(3+cosx)
limx→0\frac{2(sinx)^2}{x^2}\frac{4x}{tan4x}(3+cosx)=2×1×14×1×(3+1)=2.