devarshi-dt-logo

Question:

Divide the polynomial by the given monomial:
(i) (5x² + 6x) ÷ 3x
(ii) (3y⁸ - 8y⁶ + 5y⁴) ÷ y⁴
(iii) 8(x³y²z² + x²y³z² + x²y²z³) ÷ 4x²y²z²
(iv) (x³ + 2x² + 3x) ÷ 2x
(v) (p³q⁶ - p⁶q³) ÷ p³q³

Solution:

(i) (5x² + 6x) ÷ 3x = (5x² + 6x)/3x = x(5x + 6)/3x = (5x + 6)/3
(ii) (3y⁸ - 8y⁶ + 5y⁴) ÷ y⁴ = (3y⁸ - 8y⁶ + 5y⁴)/y⁴ = 3y⁴ - 8y² + 5
(iii) 8(x³y²z² + x²y³z² + x²y²z³) ÷ 4x²y²z² = 8(x³y²z² + x²y³z² + x²y²z³)/(4x²y²z²) = 2(x + y + z)
(iv) (x³ + 2x² + 3x) ÷ 2x = (x³ + 2x² + 3x)/2x = x(x² + 2x + 3)/2x = (x² + 2x + 3)/2
(v) (p³q⁶ - p⁶q³) ÷ p³q³ = (p³q⁶ - p⁶q³)/p³q³ = p³q³(q³ - p³)/p³q³ = q³ - p³