Eduprobe
Question:
Draw a graph of E versus r for r >> a
Solution:
Net field at P is given by
EP=EB−EA=14πε0(q(r−a)2−q(r+a)2)=q4πε04ar(r2−a2)2=14πε02pr(r2−a2)2along BP .for r>>aEP=14πε02pr3
Net field at P is given by
EP=EB−EA=14πε0(q(r−a)2−q(r+a)2)=q4πε04ar(r2−a2)2=14πε02pr(r2−a2)2along BP .for r>>aEP=14πε02pr3