Draw a triangle ABC with side BC=7 cm, ∠B=45°, ∠A=105°. Then, construct a triangle whose sides are 4/3 times the corresponding sides of triangle ABC.

In ΔABC, ∠A+∠B+∠C=180° ∴105°+45°+∠C=180° ∴∠C=30°
Constructing ΔABC:
Step 1: Draw base BC of length 7 cm.
Step 2: Draw a ray at an angle of 45° with line BC from point B.
Step 3: Draw a ray at an angle of 30° from line CB from point C and mark the intersection point of the rays from B and C as A.
Step 4: Join A−B and A−C. ΔABC is the required triangle.
For constructing ΔEBD ≅ ΔABC
Step 1: Draw a ray BX at an acute angle to line BC on the opposite side of A.
Step 2: Mark 4 equidistant points B1, B2, B3, B4 on ray BX.
Step 3: Join B3 and C.
Step 4: Draw B4D parallel to B3C and label the intersection on the extension of BC as D.
Step 5: Draw DE parallel to BA and label the intersection with the extension of BA as E
ΔEBD is the required triangle.