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Question:

Each of the following options contains a set of four molecules. Identify the option(s) where all four molecules possess a permanent dipole moment at room temperature.

NO2,NH3,POCl3,CH3C

BeCl2,CO2,BCl3,CHCl3

BF3,O3,SF6,XeF

SO2,C6H5Cl,H2Se,BrF

Solution:

Correct option is D. SO2, C6H5Cl, H2Se, BrF. All molecules in option D possess a permanent dipole moment at room temperature due to their asymmetrical molecular geometries and the presence of polar bonds. Let's examine each molecule:

  • SO2 (Sulfur dioxide): The bent molecular geometry results in a net dipole moment.
  • C6H5Cl (Chlorobenzene): The electronegativity difference between chlorine and carbon creates a polar C-Cl bond, leading to a permanent dipole moment.
  • H2Se (Hydrogen selenide): Similar to water, the bent geometry and the electronegativity difference between selenium and hydrogen result in a net dipole moment.
  • BrF (Bromine fluoride): The electronegativity difference between bromine and fluorine creates a polar bond, resulting in a permanent dipole moment.

The other options contain molecules with symmetrical geometries (like BF3, CO2, BCl3, and SF6) or molecules where the polar bonds cancel each other out, resulting in a zero net dipole moment.