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Question:

Electrolyte KCl, KNO3, HCl, NaOAc, NaCl. Λ∞ (S cm² mol⁻¹) 149.9, 145.0, 426.2, 91.0, 126.5. Calculate Λ∞ HOAc using appropriate molar conductances of the electrolytes listed above at infinite dilution in H₂O at 25°C. 390.7, 552.7, 217.5, 517.2

390.7.

517.2

217.5

552.7

Solution:

Using the given data, Λ∞HOAc = Λ∞NaOAc + Λ∞HCl - Λ∞NaCl = 91.0 + 426.2 - 126.5 cm²mol⁻¹ = 390.7 S cm²mol⁻¹