108.8eV
12.1eV
36.3eV
122.4eV
ΔU = 13.6(Z)²(1/n₁² - 1/n₂²)For Li+, Z = 3 (atomic number -1)n₁ = 1 (first Bohr orbit)n₂ = 3 (third Bohr orbit)ΔU = 13.6(3)²(1/1² - 1/3²) = 13.6 * 9 * (1 - 1/9) = 122.4 * (8/9) = 108.8 eV